Rust Program to Display Factors of a Number

Display Factors of a Number

Rust Programming Language

Problem

Rust program that displays the factors of a given number.

Input

use std::io;

fn main() {

    println!("Please enter a positive integer:");

    let mut input = String::new();

    io::stdin()

        .read_line(&mut input)

        .expect("Failed to read line");

    let input = input.trim().parse::<u32>().unwrap();

    println!("Factors of {}: ", input);

    for i in 1..=input {

        if input % i == 0 {

            println!("{}", i);

        }

    }

}{codeBox}

Output

Please enter a positive integer:

28

Factors of 28:

1

2

4

7

14

28{codeBox}

Explanation

This program prompts the user to enter a positive integer, reads the input integer from the user using the io module from Rust's standard library, and parses it into an unsigned 32-bit integer using parse::<u32>().unwrap().

We then print "Factors of [input]: " to the console.

Next, we loop from 1 to input inclusive, and in each iteration of the loop, we check if input is divisible by the current value of i (using the modulus operator %). If it is, we print the value of i to the console.

This shows the program prompting the user to enter a positive integer, the user entering the integer 28, and the program displaying the factors of 28 to the console.